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Dinu_Arya
Dinu_Arya
New Participant
May 4, 2016
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How to trigger a workflow process programmatically?

  • May 4, 2016
  • 3 replies
  • 4421 views

Hi Team,

I have written a workflow process (com.mycompany.workflow.MyWorkflowProcess) by implementing com.day.cq.workflow.exec.WorkflowProcess. I have to trigger this workflow process programmatically? The only input I got is the workflow process (i.e. com.mycompany.workflow.MyWorkflowProcess) not even the model of the workflow in which it is used.

My requirement is -

  1. Author will select the workflow from the drop-down (which is as same as the Process drop-down in the workflow Process Step)
  2. From the drop-down I will get the symbolic name of the process like com.mycompany.workflow.MyWorkflowProcess.
  3. I have to trigger this workflow programmatically.

Please help me in this.

Thanks,

AryA.

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Best answer by smacdonald2008

There are only 2 methods (not counting the Deprecated one)  exposed in the WorkFlowSession Class that starts a workflow:

WorkflowstartWorkflow(WorkflowModel model, WorkflowData data)
           Start a new Workflow instance with the given WorkflowModel and WorkflowData.
WorkflowstartWorkflow(WorkflowModel model, WorkflowData data, Dictionary<String,String> metaData)
           Deprecated. It's recommended to use #startWorkflow(WorkflowModel, WorkflowData, Map instead.
WorkflowstartWorkflow(WorkflowModel model, WorkflowData data, Map<String,Object> metaData)
           Start a new Workflow instance with the given WorkflowModel, WorkflowData and meta data.

Therefore you need a WorkflowModel and data,

In your use case - you need these as input - else it will not work.

3 replies

smacdonald2008
smacdonald2008Accepted solution
New Participant
May 4, 2016

There are only 2 methods (not counting the Deprecated one)  exposed in the WorkFlowSession Class that starts a workflow:

WorkflowstartWorkflow(WorkflowModel model, WorkflowData data)
           Start a new Workflow instance with the given WorkflowModel and WorkflowData.
WorkflowstartWorkflow(WorkflowModel model, WorkflowData data, Dictionary<String,String> metaData)
           Deprecated. It's recommended to use #startWorkflow(WorkflowModel, WorkflowData, Map instead.
WorkflowstartWorkflow(WorkflowModel model, WorkflowData data, Map<String,Object> metaData)
           Start a new Workflow instance with the given WorkflowModel, WorkflowData and meta data.

Therefore you need a WorkflowModel and data,

In your use case - you need these as input - else it will not work.

smacdonald2008
smacdonald2008
New Participant
May 4, 2016
PLACEHOLDER
Dinu_Arya
Dinu_AryaAuthor
New Participant
May 4, 2016
  Ya. I have seen that article. In that they are invoking the OSGi service and passed the model as input then started the workflow using the model path.  But in my case, I have to trigger the workflow directly with the input, com.my company.workflow. MyWorkflowProcess which implements WorkflowProcess. Any idea?
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