Please help me to fix this error "java.lang.IllegalArgumentException: Bad escape sequence: %" | Community
Skip to main content
K
kirank84421130
New Participant
March 26, 2020
Solved

Please help me to fix this error "java.lang.IllegalArgumentException: Bad escape sequence: %"

  • March 26, 2020
  • 2 replies
  • 4064 views

When I check the error log for one instance it is throwing Bad escape sequence. Please help me to fix this

ERROR* [qtp1968936611-3259627] org.apache.sling.engine.impl.parameters.ParameterSupport getRequestParameterMapInternal: Error parsing request java.lang.IllegalArgumentException: Bad escape sequence: %3Q at org.apache.sling.engine.impl.parameters.Util.parseNVPairString(Util.java:330) [org.apache.sling.engine:2.6.12] at org.apache.sling.engine.impl.parameters.Util.parseQueryString(Util.java:215) [org.apache.sling.engine:2.6.12] at org.apache.sling.engine.impl.parameters.ParameterSupport.getRequestParameterMapInternal(ParameterSupport.java:256) [org.apache.sling.engine:2.6.12] at org.apache.sling.engine.impl.parameters.ParameterSupport.getParameter(ParameterSupport.java:179) [org.apache.sling.engine:2.6.12] at org.apache.sling.engine.impl.parameters.ParameterSupportHttpServletRequestWrapper.getParameter(ParameterSupportHttpServletRequestWrapper.java:40) [org.apache.sling.engine:2.6.12] at com.day.crx.security.token.TokenCookie.fromRequest(TokenCookie.java:98) [com.day.crx.sling.crx-auth-token:2.5.36] at com.day.crx.security.token.TokenCookie.getTokenInfo(TokenCookie.java:137) [com.day.crx.sling.crx-auth-token:2.5.36] at com.day.crx.security.token.impl.TokenAuthenticationHandler.extractCredentials(TokenAuthenticationHandler.java:490) [com.day.crx.sling.crx-auth-token:2.5.36] at org.apache.sling.auth.core.impl.AuthenticationHandlerHolder.doExtractCredentials(AuthenticationHandlerHolder.java:76) [org.apache.sling.auth.core:1.4.2] at org.apache.sling.auth.core.impl.AbstractAuthenticationHandlerHolder.extractCredentials(AbstractAuthenticationHandlerHolder.java:60) [org.apache.sling.auth.core:1.4.2] at org.apache.sling.auth.core.impl.SlingAuthenticator.getAuthenticationInfo(SlingAuthenticator.java:735) [org.apache.sling.auth.core:1.4.2] at org.apache.sling.auth.core.impl.SlingAuthenticator.doHandleSecurity(SlingAuthenticator.java:483) [org.apache.sling.auth.core:1.4.2] at org.apache.sling.auth.core.impl.SlingAuthenticator.handleSecurity(SlingAuthenticator.java:460) [org.apache.sling.auth.core:1.4.2] at org.apache.sling.engine.impl.SlingHttpContext.handleSecurity(SlingHttpContext.java:131) [org.apache.sling.engine:2.6.12]

 

What was the approach to escape the % character in the URL

This post is no longer active and is closed to new replies. Need help? Start a new post to ask your question.
Best answer by Theo_Pendle

Hello 🙂

 

So if I understand correctly, you are trying to visit a URL with a '%' character in it and it is causing issues?

 

If you want to escape the '%' character you should use the following: '%25'. SO for example:

'www.example.com?percentage=25%'

becomes:

"www.example.com%3Fpercentage%3D25%25"

 

You can test this easily by opening your browser console (right here on this page if you want) by hitting F12 and then using the following native function: encodeURIComponent():

 

2 replies

joerghoh
joerghoh
Employee
March 30, 2020

It looks that your URL is incorrect: "Bad escape sequence: %3Q" means that there is a sequence "%3Q" which is considered as an URL escaped sequence, but it's not valid.

 

Can you post the complete URL (at least the part after the pagename)? How is this URL created?

    Theo_Pendle
    Theo_PendleAccepted solution
    New Participant
    March 26, 2020

    Hello 🙂

     

    So if I understand correctly, you are trying to visit a URL with a '%' character in it and it is causing issues?

     

    If you want to escape the '%' character you should use the following: '%25'. SO for example:

    'www.example.com?percentage=25%'

    becomes:

    "www.example.com%3Fpercentage%3D25%25"

     

    You can test this easily by opening your browser console (right here on this page if you want) by hitting F12 and then using the following native function: encodeURIComponent():

     

      kautuk_sahni
      kautuk_sahni
      Employee
      June 25, 2020
      Very well answered.
      Kautuk Sahni
      Terms & ConditionsAccessibility statement

      Loading footer...