Purposeful duplicates via form submission using partition id as hidden form | Community
Skip to main content
SchhorNavitas
SchhorNavitas
New Participant
February 14, 2022
Question

Purposeful duplicates via form submission using partition id as hidden form

  • February 14, 2022
  • 1 reply
  • 2756 views

Hi,

Is it possible to use lead partition as hidden field on form?

Would like to allow record with the same email to exists in multiple partitions but not on one partition using partition id as custom dedupe field.

  • There are three workspaces with each workspace links to multiple partitions
  • Ensuring that form is linked to one partition 
    • Any form submission will only create/update record of that partition only without any partition management to move record from default partition to the correct partition
Form Submission Workspace Partition Email Status
#1 A 1 a@gmail.com New record created in partition 1
#2 A 2 a@gmail.com New record created in partition 2
#3 A 1 a@gmail.com Record updated in partition 1
#4 B 3 a@gmail.com New record created in partition 3
#5 B 4 a@gmail.com New record created in partition 4
#6 B 4 a@gmail.com Record updated in partition 4

 

Thank you!

This post is no longer active and is closed to new replies. Need help? Start a new post to ask your question.

1 reply

Katja_Keesom
Katja_Keesom
Community Manager
February 15, 2022

A form submission will create the record in the workspace's default partition as a standard, so I imagine you do not need to include the partition id on the form. Other than that, you can indeed set up the partition id as a second dedupe field.

SchhorNavitas
SchhorNavitasAuthor
New Participant
February 17, 2022

Hi Katja, unfortunately, this is not possible since a workspace has access to multiple partition and the primary partition might not be the intended partition for the record. I have tested this extensively with this setup via list import and form filled out. Record will automatically created on the primary partition and will require partition management to send it to the correct partition and thus duplicate record. No issue via API as you can define it.

I am looking at alternate solution on this.

Thanks!

SanfordWhiteman
SanfordWhiteman
New Participant
February 17, 2022

Katja is referring to having the partition be part of a compound dedupe key. You can’t do that yourself, it’s done by Support.

    Terms & ConditionsAccessibility statement

    Loading footer...